Integrand size = 26, antiderivative size = 116 \[ \int \frac {c+d x^2}{\sqrt {e x} \left (a+b x^2\right )^{7/4}} \, dx=\frac {2 (b c-a d) \sqrt {e x}}{3 a b e \left (a+b x^2\right )^{3/4}}-\frac {2 (2 b c+a d) \left (1+\frac {a}{b x^2}\right )^{3/4} (e x)^{3/2} \operatorname {EllipticF}\left (\frac {1}{2} \cot ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right ),2\right )}{3 a^{3/2} \sqrt {b} e^2 \left (a+b x^2\right )^{3/4}} \]
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Time = 0.06 (sec) , antiderivative size = 116, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {468, 335, 243, 342, 281, 237} \[ \int \frac {c+d x^2}{\sqrt {e x} \left (a+b x^2\right )^{7/4}} \, dx=\frac {2 \sqrt {e x} (b c-a d)}{3 a b e \left (a+b x^2\right )^{3/4}}-\frac {2 (e x)^{3/2} \left (\frac {a}{b x^2}+1\right )^{3/4} (a d+2 b c) \operatorname {EllipticF}\left (\frac {1}{2} \cot ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right ),2\right )}{3 a^{3/2} \sqrt {b} e^2 \left (a+b x^2\right )^{3/4}} \]
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Rule 237
Rule 243
Rule 281
Rule 335
Rule 342
Rule 468
Rubi steps \begin{align*} \text {integral}& = \frac {2 (b c-a d) \sqrt {e x}}{3 a b e \left (a+b x^2\right )^{3/4}}+\frac {\left (2 \left (b c+\frac {a d}{2}\right )\right ) \int \frac {1}{\sqrt {e x} \left (a+b x^2\right )^{3/4}} \, dx}{3 a b} \\ & = \frac {2 (b c-a d) \sqrt {e x}}{3 a b e \left (a+b x^2\right )^{3/4}}+\frac {(2 (2 b c+a d)) \text {Subst}\left (\int \frac {1}{\left (a+\frac {b x^4}{e^2}\right )^{3/4}} \, dx,x,\sqrt {e x}\right )}{3 a b e} \\ & = \frac {2 (b c-a d) \sqrt {e x}}{3 a b e \left (a+b x^2\right )^{3/4}}+\frac {\left (2 (2 b c+a d) \left (1+\frac {a}{b x^2}\right )^{3/4} (e x)^{3/2}\right ) \text {Subst}\left (\int \frac {1}{\left (1+\frac {a e^2}{b x^4}\right )^{3/4} x^3} \, dx,x,\sqrt {e x}\right )}{3 a b e \left (a+b x^2\right )^{3/4}} \\ & = \frac {2 (b c-a d) \sqrt {e x}}{3 a b e \left (a+b x^2\right )^{3/4}}-\frac {\left (2 (2 b c+a d) \left (1+\frac {a}{b x^2}\right )^{3/4} (e x)^{3/2}\right ) \text {Subst}\left (\int \frac {x}{\left (1+\frac {a e^2 x^4}{b}\right )^{3/4}} \, dx,x,\frac {1}{\sqrt {e x}}\right )}{3 a b e \left (a+b x^2\right )^{3/4}} \\ & = \frac {2 (b c-a d) \sqrt {e x}}{3 a b e \left (a+b x^2\right )^{3/4}}-\frac {\left ((2 b c+a d) \left (1+\frac {a}{b x^2}\right )^{3/4} (e x)^{3/2}\right ) \text {Subst}\left (\int \frac {1}{\left (1+\frac {a e^2 x^2}{b}\right )^{3/4}} \, dx,x,\frac {1}{e x}\right )}{3 a b e \left (a+b x^2\right )^{3/4}} \\ & = \frac {2 (b c-a d) \sqrt {e x}}{3 a b e \left (a+b x^2\right )^{3/4}}-\frac {2 (2 b c+a d) \left (1+\frac {a}{b x^2}\right )^{3/4} (e x)^{3/2} F\left (\left .\frac {1}{2} \cot ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )\right |2\right )}{3 a^{3/2} \sqrt {b} e^2 \left (a+b x^2\right )^{3/4}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.05 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.68 \[ \int \frac {c+d x^2}{\sqrt {e x} \left (a+b x^2\right )^{7/4}} \, dx=\frac {2 x \left (b c-a d+(2 b c+a d) \left (1+\frac {b x^2}{a}\right )^{3/4} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {3}{4},\frac {5}{4},-\frac {b x^2}{a}\right )\right )}{3 a b \sqrt {e x} \left (a+b x^2\right )^{3/4}} \]
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\[\int \frac {d \,x^{2}+c}{\sqrt {e x}\, \left (b \,x^{2}+a \right )^{\frac {7}{4}}}d x\]
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\[ \int \frac {c+d x^2}{\sqrt {e x} \left (a+b x^2\right )^{7/4}} \, dx=\int { \frac {d x^{2} + c}{{\left (b x^{2} + a\right )}^{\frac {7}{4}} \sqrt {e x}} \,d x } \]
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Result contains complex when optimal does not.
Time = 18.12 (sec) , antiderivative size = 78, normalized size of antiderivative = 0.67 \[ \int \frac {c+d x^2}{\sqrt {e x} \left (a+b x^2\right )^{7/4}} \, dx=- \frac {d {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{2}, \frac {7}{4} \\ \frac {3}{2} \end {matrix}\middle | {\frac {a e^{i \pi }}{b x^{2}}} \right )}}{b^{\frac {7}{4}} \sqrt {e} x} + \frac {c \sqrt {x} \Gamma \left (\frac {1}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{4}, \frac {7}{4} \\ \frac {5}{4} \end {matrix}\middle | {\frac {b x^{2} e^{i \pi }}{a}} \right )}}{2 a^{\frac {7}{4}} \sqrt {e} \Gamma \left (\frac {5}{4}\right )} \]
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\[ \int \frac {c+d x^2}{\sqrt {e x} \left (a+b x^2\right )^{7/4}} \, dx=\int { \frac {d x^{2} + c}{{\left (b x^{2} + a\right )}^{\frac {7}{4}} \sqrt {e x}} \,d x } \]
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\[ \int \frac {c+d x^2}{\sqrt {e x} \left (a+b x^2\right )^{7/4}} \, dx=\int { \frac {d x^{2} + c}{{\left (b x^{2} + a\right )}^{\frac {7}{4}} \sqrt {e x}} \,d x } \]
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Timed out. \[ \int \frac {c+d x^2}{\sqrt {e x} \left (a+b x^2\right )^{7/4}} \, dx=\int \frac {d\,x^2+c}{\sqrt {e\,x}\,{\left (b\,x^2+a\right )}^{7/4}} \,d x \]
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